English: Drawn without vanishing points;

To start with consider the base scale of the drawing. The station point, the "diorama peephole" through which we are looking, is at an altitude of 34 and one half inches. In the picture the horizon is at 8 and three quarters from the base edge of the paper. If you divide 8 and 3/4 by 34 and 1/2 you get a base scale of 35/138 of life. Since the tiles of the floor are 8 inches square then that means in the picture at the base edge they are 2 and 1/32 inches apart. I round everything off to 1/32 inches because that is the ruler I am using. The station point is on a line 4 and 10/32 inches from the right side of the paper. So if you label anything on the right side of the station point as positive, and what is on the left side as negative, then the position of the base lines of the tiles are -x (5 and 15/16; 3 and 29/32; 1 and 7/8) and then +x (5/32; 2 and 3/16; 4 and 7/32). In practice all you have to do is to measure any one of those points from the right side of the paper and then put each of the others at 2 and 1/32 inches apart. In that case the last point named, 4 and 7/32, would be 3/32 inches from the right side. The next question to consider is "How do we come up with where the next horizontal lines would be on the paper when it is 8 inches farther away?

              The base is 4 times 34 and 1/2 inches away, or in other words the distance to the first edge of the floor we see is 11 and 1/2 feet , and if we add 8 inches, or 8/12 feet to that, we come up with a distance of 12 and 1/6 feet. To find how far that is on the paper I used this formula :

(8 and 3/4 - ((11 and 1/2 divided by 12 and 1/6) times 8 and 3/4))

That equals 35/73 and that times 32 is rounded to 15. So the next horizontal line for the tiles is 15/32 inches from the base.

The scale at that distance is ((8 and 3/4 - 15/32) divided by 8 and 3/4) which is 53/56 times the base scale, and that also means that the converging lines for the tiles are 1 and 15/32 inches apart. I can take the position of any point on the base and multiply it by 53/56 and I get the position of the new point. That's the way I did the rest of the tiles.

Let me tell you about the distance and scale of the first wall. The base of the first wall is 6 and 1/2 inches from the base.

((8 and 3/4 divided by (8 and 3/4 - 6 and 1/2)) times 11 and 1/2)= 44 feet and 9 inches, if you round it off.

Here's the scale:

(( 8 and 3/4 - 6 and 1/2) divided by 8 and 3/4)) times 35/138) = 3/46 times life. The blocks are 18 inches on each side, including the joints.

So 3/46 times 18 = 1 and 3/16 inches. That is the size of those blocks in the drawing, and it is also the scale of everything on that wall, except the front of the fountain, which is closer to the viewer than the back of the fountain on the wall. The fountain is slightly higher than the station point and so since the back part is at a slightly smaller scale and recedes downwards . That accounts for the amount of the curve upward I put in the front edge of the fountain. Using this method you can figure out how to draw circles in perspective.