File:Diagonal argument 01.pdf

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English: An illustration of Cantor's diagonal argument (in base 2) for the existence of uncountable sets. The sequence at the bottom cannot occur anywhere in the enumeration of sequences above. (Adapted from File:Diagonal argument 2.svg; see File:Diagonal argument powerset.pdf for a similar version for power sets.)
Date
Source Own work
Author Jochen Burghardt
Other versions File:Diagonal argument 01 svg.svg
LaTeX source Code
\documentclass{article}
\usepackage[pdftex]{color}
\usepackage[paperwidth=50mm,paperheight=65mm]{geometry}
\setlength{\topmargin}{-36mm}
\setlength{\textwidth}{50mm}
\setlength{\textheight}{65mm}
\setlength{\oddsidemargin}{-23mm}
\setlength{\parindent}{0mm}
\definecolor{cPos}      {rgb}{0.99,0.00,0.00}
\definecolor{cNeg}      {rgb}{0.00,0.00,0.99}
\pagestyle{empty}
\newcommand{\0}[1]{\textcolor{cPos}{#1}}
\newcommand{\1}[1]{\textcolor{cNeg}{#1}}

\begin{document}
$\begin{array}{|*{14}{@{\;}c}|}
\hline
s_1     & =     & \00   & 0     & 0     & 0     & 0     & 0     & 0     & 0     & 0     & 0     & 0     & \ldots        \\      % periodic 0
s_2     & =     & 1     & \01   & 1     & 1     & 1     & 1     & 1     & 1     & 1     & 1     & 1     & \ldots        \\      % periodic 1
s_3     & =     & 0     & 1     & \00   & 1     & 0     & 1     & 0     & 1     & 0     & 1     & 0     & \ldots        \\      % periodic 0,1
s_4     & =     & 1     & 0     & 1     & \00   & 1     & 0     & 1     & 0     & 1     & 0     & 1     & \ldots        \\      % periodic 1,0
s_5     & =     & 1     & 1     & 0     & 1     & \00   & 1     & 1     & 0     & 1     & 0     & 1     & \ldots        \\      % periodic 1,1,0,1,0
s_6     & =     & 0     & 0     & 1     & 1     & 0     & \01   & 1     & 0     & 1     & 1     & 0     & \ldots        \\      % 0, periodic 0,1,1
s_7     & =     & 1     & 0     & 0     & 0     & 1     & 0     & \00   & 0     & 1     & 0     & 0     & \ldots        \\      % periodic 1,0,0,0
s_8     & =     & 0     & 0     & 1     & 1     & 0     & 0     & 1     & \01   & 0     & 0     & 1     & \ldots        \\      % periodic 0,0,1,1
s_9     & =     & 1     & 1     & 0     & 0     & 1     & 1     & 0     & 0     & \01   & 1     & 0     & \ldots        \\      % periodic 1,1,0,0
s_{10}  & =     & 1     & 1     & 0     & 1     & 1     & 1     & 0     & 0     & 1     & \00   & 1     & \ldots        \\      % binary numbers 1, 10, 11, 100, 101, ...)
s_{11}  & =     & 1     & 1     & 0     & 1     & 0     & 1     & 0     & 0     & 1     & 0     & \00   & \ldots        \\      % 1 whenever new number starts in s_{10}
\vdots  &       & \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \ddots     \\
\hline
\multicolumn{10}{c}{}   \\
\hline
s       & =     & \11   & \10   & \11   & \11   & \11   & \10   & \11   & \10   & \10   & \11   & \11   & \ldots        \\
\hline
\end{array}$
\end{document}

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Date/TimeThumbnailDimensionsUserComment
current10:07, 11 December 2013Thumbnail for version as of 10:07, 11 December 2013293 × 383 (11 KB)Jochen Burghardt (talk | contribs)as suggested by RJGray on my EN talk page:"Try removing the commas (and perhaps spacing the 0s and 1s closer together?)"
12:32, 10 December 2013No thumbnail0 × 0 (15 KB)Jochen Burghardt (talk | contribs)more enumeration elements, longer sequences
11:36, 10 December 2013No thumbnail0 × 0 (14 KB)Jochen Burghardt (talk | contribs)User created page with UploadWizard

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