File:Geostationary227x221simple3D.gif

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DescriptionGeostationary227x221simple3D.gif	English: A geostationary orbit can only be achieved at an altitude very close to 35,786 km (22,236 mi), and directly above the equator. This equates to an orbital velocity of 3.07 km/s (1.91 mi/s) or a period of 1,436 minutes, which equates to almost exactly one sidereal day or 23.934461223 hours. This makes sense considering that the satellite must be locked to the Earth's rotational period in order to have a stationary footprint on the ground. In practice, this means that all geostationary satellites have to exist on this ring http://weelookang.blogspot.com/2010/07/ejs-open-source-geostationary-satellite.html
Date	26 June 2011
Source	Own work
Author	Lookang many thanks to author of original simulation = Francisco Esquembre author of Easy Java Simulation = Francisco Esquembre

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	Date/Time	Thumbnail	Dimensions	User	Comment
current	15:39, 26 June 2011		227 × 221 (750 KB)	Lookang (talk \| contribs)

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