File:Edmund Andros.jpg

Edmund_Andros.jpg(313 × 396 pixels, file size: 36 KB, MIME type: image/jpeg)

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English: Sir Edmund Andros
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This is a faithful photographic reproduction of a two-dimensional, public domain work of art. The work of art itself is in the public domain for the following reason:
Public domain
Public domain
This media file is in the public domain in the United States. This applies to U.S. works where the copyright has expired, often because its first publication occurred prior to January 1, 1929, and if not then due to lack of notice or renewal. See this page for further explanation.

United States
United States
This image might not be in the public domain outside of the United States; this especially applies in the countries and areas that do not apply the rule of the shorter term for US works, such as Canada, Mainland China (not Hong Kong or Macao), Germany, Mexico, and Switzerland. The creator and year of publication are essential information and must be provided. See Wikipedia:Public domain and Wikipedia:Copyrights for more details.
The official position taken by the Wikimedia Foundation is that "faithful reproductions of two-dimensional public domain works of art are public domain".
This photographic reproduction is therefore also considered to be in the public domain in the United States. In other jurisdictions, re-use of this content may be restricted; see Reuse of PD-Art photographs for details.

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Transferred from en.wikipedia to Commons.

The original description page was here. All following user names refer to en.wikipedia.
  • 2006-02-08 03:18 Hugh Manatee 313×396× (36780 bytes) Sir Edmund Andros

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Date/TimeThumbnailDimensionsUserComment
current18:15, 13 July 2012Thumbnail for version as of 18:15, 13 July 2012313 × 396 (36 KB)MGA73bot2 (talk | contribs) {{BotMoveToCommons|en.wikipedia|year={{subst:CURRENTYEAR}}|month={{subst:CURRENTMONTHNAME}}|day={{subst:CURRENTDAY}}}} {{Information |Description={{en|Sir Edmund Andros}} |Source=Transferred from [http://en.wikipedia.org en.wikipedia] |Date={{Date|20...

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