Template:Combinatorics; 5 choose 3

	without repetition	with repetition
variations (tuples)	$~{5 \choose 3}{\cdot 3!}~=~60~$	$~5^{3}~=~125~$ In lexicographical order
combinations (sets)	$~{5 \choose 3}~=~10~$	$~\left(\!\!{5 \choose 3}\!\!\right)~=~{7 \choose 3}~=~35~$ In lexicographical order